...成员函数doubleDistance(const& Point),求两点的距离。

发布网友 发布时间:2024-10-23 21:54

我来回答

2个回答

热心网友 时间:2024-11-05 19:28

//定义Point类
class Point
{
public Point(){x = y = 0;}
public Point(double x,double y){this.x = x;this.y = y;}
public double Distance(const Point &p){return sqrt((x-p.x)*(x-p.x)+(y-p.y)*(y-p*y));}
public double x,y;
};

//测试代码
#include <iostream>
#include <math>
using namespace std;

class Point
{
public Point(){x = y = 0;}
public Point(double x,double y){this.x = x;this.y = y;}
public double Distance(const Point &p){return sqrt((x-p.x)*(x-p.x)+(y-p.y)*(y-p*y));}
public double x,y;
};

void main(){
Point p1(2,-3.5),p2(-2.1,3);
cout<<"距离为:"<<p1.Distance(p2)<<endl;
}

热心网友 时间:2024-11-05 19:27

#include<iostream>
#include<cmath>
using namespace std;
class Point //点类

{
public:

double sqrtToPoint(Point& q) {return sqrt((X-q.X)*(X-q.X)+(Y-q.Y)*(Y-q.Y));};//两点距离函数
Point ( float a = 0,float b = 0 ) //构造函数

{
X=a;
Y=b;
}

float Dis(Point& p, Point& q);

void Print()
{
cout << "X=" << X <<endl;
cout << "Y=" << Y <<endl;
}
private:
float X, Y;
};

float Point::Dis(Point& p, Point& q)
{
float result;
result = p.sqrtToPoint(q); //调用内部函数

cout << result << endl;
return result;
}
void main()
{
cout<<"测试两点为p(2,11),q(2, 21)"<<endl;

cout<<"p,q 之间距离为"<<ends;

Point d;

Point p(2, 11), q(2, 21);

d.Dis(p, q);

}

声明声明:本网页内容为用户发布,旨在传播知识,不代表本网认同其观点,若有侵权等问题请及时与本网联系,我们将在第一时间删除处理。E-MAIL:11247931@qq.com