发布网友 发布时间:2024-10-24 11:06
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热心网友 时间:2024-10-24 15:52
a20:=sum(amount,20)/sum(v,20)/100;a40:=sum(amount,40)/sum(v,40)/100;a60:=sum(amount,60)/sum(v,60)/100;max(a20,a40,a60)/min(a20,a40,a60)<1.05 and cross(c,max(a20,a40,a60));